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(7+x)5=(3x+1)3
We move all terms to the left:
(7+x)5-((3x+1)3)=0
We add all the numbers together, and all the variables
(x+7)5-((3x+1)3)=0
We multiply parentheses
5x-((3x+1)3)+35=0
We calculate terms in parentheses: -((3x+1)3), so:We get rid of parentheses
(3x+1)3
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
5x-9x-3+35=0
We add all the numbers together, and all the variables
-4x+32=0
We move all terms containing x to the left, all other terms to the right
-4x=-32
x=-32/-4
x=+8
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