(7+y)(4y+1)=0

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Solution for (7+y)(4y+1)=0 equation:


Simplifying
(7 + y)(4y + 1) = 0

Reorder the terms:
(7 + y)(1 + 4y) = 0

Multiply (7 + y) * (1 + 4y)
(7(1 + 4y) + y(1 + 4y)) = 0
((1 * 7 + 4y * 7) + y(1 + 4y)) = 0
((7 + 28y) + y(1 + 4y)) = 0
(7 + 28y + (1 * y + 4y * y)) = 0
(7 + 28y + (1y + 4y2)) = 0

Combine like terms: 28y + 1y = 29y
(7 + 29y + 4y2) = 0

Solving
7 + 29y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(7 + y)(1 + 4y) = 0

Subproblem 1

Set the factor '(7 + y)' equal to zero and attempt to solve: Simplifying 7 + y = 0 Solving 7 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + y = 0 + -7 y = 0 + -7 Combine like terms: 0 + -7 = -7 y = -7 Simplifying y = -7

Subproblem 2

Set the factor '(1 + 4y)' equal to zero and attempt to solve: Simplifying 1 + 4y = 0 Solving 1 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4y = 0 + -1 4y = 0 + -1 Combine like terms: 0 + -1 = -1 4y = -1 Divide each side by '4'. y = -0.25 Simplifying y = -0.25

Solution

y = {-7, -0.25}

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