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(7+z)(4z+2)=0
We add all the numbers together, and all the variables
(z+7)(4z+2)=0
We multiply parentheses ..
(+4z^2+2z+28z+14)=0
We get rid of parentheses
4z^2+2z+28z+14=0
We add all the numbers together, and all the variables
4z^2+30z+14=0
a = 4; b = 30; c = +14;
Δ = b2-4ac
Δ = 302-4·4·14
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-26}{2*4}=\frac{-56}{8} =-7 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+26}{2*4}=\frac{-4}{8} =-1/2 $
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