(7+z)(8+z)=0

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Solution for (7+z)(8+z)=0 equation:



(7+z)(8+z)=0
We add all the numbers together, and all the variables
(z+7)(z+8)=0
We multiply parentheses ..
(+z^2+8z+7z+56)=0
We get rid of parentheses
z^2+8z+7z+56=0
We add all the numbers together, and all the variables
z^2+15z+56=0
a = 1; b = 15; c = +56;
Δ = b2-4ac
Δ = 152-4·1·56
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-1}{2*1}=\frac{-16}{2} =-8 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+1}{2*1}=\frac{-14}{2} =-7 $

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