(7-12i)(7+12i)=0

Solution for (7-12i)(7+12i)=0 equation:

(7-12i)(7+12i)=0

We add all the numbers together, and all the variables

(-12i+7)(12i+7)=0

We multiply parentheses ..

(-144i^2-84i+84i+49)=0

We get rid of parentheses

-144i^2-84i+84i+49=0

We add all the numbers together, and all the variables

-144i^2+49=0

a = -144; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-144)·49
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*-144}=\frac{-168}{-288}
=7/12
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*-144}=\frac{168}{-288}
=-7/12
$