(7-2k)/(2-k)=12/5

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Solution for (7-2k)/(2-k)=12/5 equation: 



(7-2k)/(2-k)=12/5

We move all terms to the left:

(7-2k)/(2-k)-(12/5)=0



Domain of the equation: (2-k)!=0

We move all terms containing k to the left, all other terms to the right

-k!=-2

k!=-2/-1

k!=+2

k∈R



We add all the numbers together, and all the variables

(-2k+7)/(-1k+2)-(+12/5)=0

We get rid of parentheses

(-2k+7)/(-1k+2)-12/5=0

We calculate fractions


(-10k+35)/(-5k+10)+(12k-24)/(-5k+10)=0

We multiply all the terms by the denominator


(-10k+35)+(12k-24)=0

We get rid of parentheses

-10k+12k+35-24=0

We add all the numbers together, and all the variables

2k+11=0

We move all terms containing k to the left, all other terms to the right

2k=-11

k=-11/2

k=-5+1/2

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