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(7-2x)x=6
We move all terms to the left:
(7-2x)x-(6)=0
We add all the numbers together, and all the variables
(-2x+7)x-6=0
We multiply parentheses
-2x^2+7x-6=0
a = -2; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·(-2)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*-2}=\frac{-8}{-4} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*-2}=\frac{-6}{-4} =1+1/2 $
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