(7-2y+2)=(8+5y+4)-31

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Solution for (7-2y+2)=(8+5y+4)-31 equation: 



(7-2y+2)=(8+5y+4)-31

We move all terms to the left:

(7-2y+2)-((8+5y+4)-31)=0

We add all the numbers together, and all the variables

(-2y+9)-((5y+12)-31)=0

We get rid of parentheses

-2y-((5y+12)-31)+9=0



We calculate terms in parentheses: -((5y+12)-31), so:

(5y+12)-31

We get rid of parentheses

5y+12-31

We add all the numbers together, and all the variables

5y-19

Back to the equation:

-(5y-19)



We get rid of parentheses

-2y-5y+19+9=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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