(7-3w)/5=(-8-2w)/3

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Solution for (7-3w)/5=(-8-2w)/3 equation: 



(7-3w)/5=(-8-2w)/3

We move all terms to the left:

(7-3w)/5-((-8-2w)/3)=0

We add all the numbers together, and all the variables

(-3w+7)/5-((-2w-8)/3)=0

We calculate fractions


(-3w)/()+(-((-2w-8)*5)/()=0



We calculate terms in parentheses: +(-((-2w-8)*5)/(), so:

-((-2w-8)*5)/(

We multiply all the terms by the denominator


-((-2w-8)*5)



We calculate terms in parentheses: -((-2w-8)*5), so:

(-2w-8)*5

We multiply parentheses

-10w-40

Back to the equation:

-(-10w-40)



We get rid of parentheses

10w+40

Back to the equation:

+(10w+40)



We get rid of parentheses

(-3w)/()+10w+40=0

We multiply all the terms by the denominator


(-3w)+10w*()+40*()=0

We add all the numbers together, and all the variables

(-3w)+10w*()=0

We get rid of parentheses

-3w+10w*()=0

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