(7-3x)(10x-4)=0

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Solution for (7-3x)(10x-4)=0 equation:



(7-3x)(10x-4)=0
We add all the numbers together, and all the variables
(-3x+7)(10x-4)=0
We multiply parentheses ..
(-30x^2+12x+70x-28)=0
We get rid of parentheses
-30x^2+12x+70x-28=0
We add all the numbers together, and all the variables
-30x^2+82x-28=0
a = -30; b = 82; c = -28;
Δ = b2-4ac
Δ = 822-4·(-30)·(-28)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-58}{2*-30}=\frac{-140}{-60} =2+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+58}{2*-30}=\frac{-24}{-60} =2/5 $

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