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(7-3x)(7-3x)=81
We move all terms to the left:
(7-3x)(7-3x)-(81)=0
We add all the numbers together, and all the variables
(-3x+7)(-3x+7)-81=0
We multiply parentheses ..
(+9x^2-21x-21x+49)-81=0
We get rid of parentheses
9x^2-21x-21x+49-81=0
We add all the numbers together, and all the variables
9x^2-42x-32=0
a = 9; b = -42; c = -32;
Δ = b2-4ac
Δ = -422-4·9·(-32)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-54}{2*9}=\frac{-12}{18} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+54}{2*9}=\frac{96}{18} =5+1/3 $
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