(7-3x)/5=(3x-2)/7

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Solution for (7-3x)/5=(3x-2)/7 equation: 



(7-3x)/5=(3x-2)/7

We move all terms to the left:

(7-3x)/5-((3x-2)/7)=0

We add all the numbers together, and all the variables

(-3x+7)/5-((3x-2)/7)=0

We calculate fractions


(-3x)/()+(-((3x-2)*5)/()=0



We calculate terms in parentheses: +(-((3x-2)*5)/(), so:

-((3x-2)*5)/(

We multiply all the terms by the denominator


-((3x-2)*5)



We calculate terms in parentheses: -((3x-2)*5), so:

(3x-2)*5

We multiply parentheses

15x-10

Back to the equation:

-(15x-10)



We get rid of parentheses

-15x+10

Back to the equation:

+(-15x+10)



We get rid of parentheses

(-3x)/()-15x+10=0

We multiply all the terms by the denominator


(-3x)-15x*()+10*()=0

We add all the numbers together, and all the variables

(-3x)-15x*()=0

We get rid of parentheses

-3x-15x*()=0

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