(7-3x)/6=(1/3)-(x/2)

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Solution for (7-3x)/6=(1/3)-(x/2) equation: 


x in (-oo:+oo)

(7-(3*x))/6 = 1/3-(x/2) // - 1/3-(x/2)

(7-(3*x))/6+x/2-(1/3) = 0

(7-3*x)/6+x/2-1/3 = 0

(2*3*(7-3*x))/(2*3*6)+(3*6*x)/(2*3*6)+(-1*2*6)/(2*3*6) = 0

2*3*(7-3*x)+3*6*x-1*2*6 = 0

42-12 = 0

30 = 0

30/(2*3*6) = 0

30/(2*3*6) = 0 // * 2*3*6

30 = 0

x belongs to the empty set

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