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(7-3y)(5+y)=0
We add all the numbers together, and all the variables
(-3y+7)(y+5)=0
We multiply parentheses ..
(-3y^2-15y+7y+35)=0
We get rid of parentheses
-3y^2-15y+7y+35=0
We add all the numbers together, and all the variables
-3y^2-8y+35=0
a = -3; b = -8; c = +35;
Δ = b2-4ac
Δ = -82-4·(-3)·35
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-22}{2*-3}=\frac{-14}{-6} =2+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+22}{2*-3}=\frac{30}{-6} =-5 $
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