(7-4x)(1/2)+(3-2x)(1/2)=1

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Solution for (7-4x)(1/2)+(3-2x)(1/2)=1 equation: 



(7-4x)(1/2)+(3-2x)(1/2)=1

We move all terms to the left:

(7-4x)(1/2)+(3-2x)(1/2)-(1)=0

We add all the numbers together, and all the variables

(-4x+7)(+1/2)+(-2x+3)(+1/2)-1=0

We multiply parentheses ..

(-4x^2+7*1/2)+(-2x+3)(+1/2)-1=0

We multiply all the terms by the denominator


(-4x^2+7*1+(-2x+3)(+1-1*2)=0



We calculate terms in parentheses: +(-4x^2+7*1+(-2x+3)(+1-1*2), so:

-4x^2+7*1+(-2x+3)(+1-1*2

determiningTheFunctionDomain
-4x^2+(-2x+3)(+1-1*2+7*1

Back to the equation:

+(-4x^2+(-2x+3)(+1-1*2+7*1)



We add all the numbers together, and all the variables

(-4x^2+(-2x+3)6=0

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