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(7-4x)(7x)=(3-4x)(7x+7)
We move all terms to the left:
(7-4x)(7x)-((3-4x)(7x+7))=0
We add all the numbers together, and all the variables
(-4x+7)7x-((-4x+3)(7x+7))=0
We multiply parentheses
-28x^2+49x-((-4x+3)(7x+7))=0
We multiply parentheses ..
-28x^2-((-28x^2-28x+21x+21))+49x=0
We calculate terms in parentheses: -((-28x^2-28x+21x+21)), so:We get rid of parentheses
(-28x^2-28x+21x+21)
We get rid of parentheses
-28x^2-28x+21x+21
We add all the numbers together, and all the variables
-28x^2-7x+21
Back to the equation:
-(-28x^2-7x+21)
-28x^2+28x^2+7x+49x-21=0
We add all the numbers together, and all the variables
56x-21=0
We move all terms containing x to the left, all other terms to the right
56x=21
x=21/56
x=3/8
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