(7-b)+(3b=2)

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Solution for (7-b)+(3b=2) equation:



(7-b)+(3b=2)
We move all terms to the left:
(7-b)+(3b-(2))=0
We add all the numbers together, and all the variables
(-1b+7)+(3b-2)=0
We get rid of parentheses
-1b+3b+7-2=0
We add all the numbers together, and all the variables
2b+5=0
We move all terms containing b to the left, all other terms to the right
2b=-5
b=-5/2
b=-2+1/2

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