(7-x)(4x+9)=0

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Solution for (7-x)(4x+9)=0 equation:



(7-x)(4x+9)=0
We add all the numbers together, and all the variables
(-1x+7)(4x+9)=0
We multiply parentheses ..
(-4x^2-9x+28x+63)=0
We get rid of parentheses
-4x^2-9x+28x+63=0
We add all the numbers together, and all the variables
-4x^2+19x+63=0
a = -4; b = 19; c = +63;
Δ = b2-4ac
Δ = 192-4·(-4)·63
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-37}{2*-4}=\frac{-56}{-8} =+7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+37}{2*-4}=\frac{18}{-8} =-2+1/4 $

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