(7-x)2=(x+3)2

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Solution for (7-x)2=(x+3)2 equation: 



(7-x)2=(x+3)2

We move all terms to the left:

(7-x)2-((x+3)2)=0

We add all the numbers together, and all the variables

(-1x+7)2-((x+3)2)=0

We multiply parentheses

-2x-((x+3)2)+14=0



We calculate terms in parentheses: -((x+3)2), so:

(x+3)2

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

-2x-2x-6+14=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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