(7-y)/3=2

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Solution for (7-y)/3=2 equation: 


y in (-oo:+oo)

(7-y)/3 = 2 // - 2

(7-y)/3-2 = 0

(7-y)/3+(-2*3)/3 = 0

7-y-2*3 = 0

1-y = 0

(1-y)/3 = 0

(1-y)/3 = 0 // * 3

1-y = 0

1-y = 0 // - 1

-y = -1 // * -1

y = 1

y = 1

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