(7.3x)(x+2)=5

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Solution for (7.3x)(x+2)=5 equation:



(7.3x)(x+2)=5
We move all terms to the left:
(7.3x)(x+2)-(5)=0
We add all the numbers together, and all the variables
(+7.3x)(x+2)-5=0
We multiply parentheses ..
(+7x^2+14x)-5=0
We get rid of parentheses
7x^2+14x-5=0
a = 7; b = 14; c = -5;
Δ = b2-4ac
Δ = 142-4·7·(-5)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4\sqrt{21}}{2*7}=\frac{-14-4\sqrt{21}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4\sqrt{21}}{2*7}=\frac{-14+4\sqrt{21}}{14} $

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