(7/(2x+1))-(8x/(2x-1))=4

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Solution for (7/(2x+1))-(8x/(2x-1))=4 equation: 



(7/(2x+1))-(8x/(2x-1))=4

We move all terms to the left:

(7/(2x+1))-(8x/(2x-1))-(4)=0



Domain of the equation: (2x+1))!=0

x∈R





Domain of the equation: (2x-1))!=0

x∈R



We calculate fractions


(-16x^2-8x)/((2x+1))*2x+(14x-7)/((2x+1))*2x-4=0

We multiply all the terms by the denominator


(-16x^2-8x)+(14x-7)-4*((2x+1))*2x=0

We get rid of parentheses

-16x^2-8x+14x-4*((2x+1))*2x-7=0

We add all the numbers together, and all the variables

-16x^2+6x-4*((2x+1))*2x-7=0

We move all terms containing x to the left, all other terms to the right

-16x^2+6x-4*((2x+1))*2x=7

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