(7/(4x-1))=(2/(x+5))

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Solution for (7/(4x-1))=(2/(x+5)) equation: 


D( x )

x+5 = 0

4*x-1 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

4*x-1 = 0

4*x-1 = 0

4*x-1 = 0 // + 1

4*x = 1 // : 4

x = 1/4

x in (-oo:-5) U (-5:1/4) U (1/4:+oo)

7/(4*x-1) = 2/(x+5) // - 2/(x+5)

7/(4*x-1)-(2/(x+5)) = 0

7/(4*x-1)-2*(x+5)^-1 = 0

7/(4*x-1)-2/(x+5) = 0

(7*(x+5))/((4*x-1)*(x+5))+(-2*(4*x-1))/((4*x-1)*(x+5)) = 0

7*(x+5)-2*(4*x-1) = 0

37-x = 0

(37-x)/((4*x-1)*(x+5)) = 0

(37-x)/((4*x-1)*(x+5)) = 0 // * (4*x-1)*(x+5)

37-x = 0

37-x = 0 // - 37

-x = -37 // * -1

x = 37

x = 37

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