(7/(4z-3))=(4/(9z))

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Solution for (7/(4z-3))=(4/(9z)) equation:


D( z )

9*z = 0

4*z-3 = 0

9*z = 0

9*z = 0

9*z = 0 // : 9

z = 0

4*z-3 = 0

4*z-3 = 0

4*z-3 = 0 // + 3

4*z = 3 // : 4

z = 3/4

z in (-oo:0) U (0:3/4) U (3/4:+oo)

7/(4*z-3) = 4/(9*z) // - 4/(9*z)

7/(4*z-3)-(4/(9*z)) = 0

7/(4*z-3)+(-4/9)*z^-1 = 0

7/(4*z-3)-4/(9*z) = 0

(7*9*z)/(9*z*(4*z-3))+(-4*(4*z-3))/(9*z*(4*z-3)) = 0

7*9*z-4*(4*z-3) = 0

47*z+12 = 0

(47*z+12)/(9*z*(4*z-3)) = 0

(47*z+12)/(9*z*(4*z-3)) = 0 // * 9*z*(4*z-3)

47*z+12 = 0

47*z+12 = 0 // - 12

47*z = -12 // : 47

z = -12/47

z = -12/47

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