(7/(x-3))+(8+x)=9

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Solution for (7/(x-3))+(8+x)=9 equation: 



(7/(x-3))+(8+x)=9

We move all terms to the left:

(7/(x-3))+(8+x)-(9)=0



Domain of the equation: (x-3))!=0

x∈R



We add all the numbers together, and all the variables

(7/(x-3))+(x+8)-9=0

We get rid of parentheses

(7/(x-3))+x+8-9=0

We multiply all the terms by the denominator


(7+x*(x-3))+8*(x-3))-9*(x-3))=0



We calculate terms in parentheses: +(7+x*(x-3)), so:

7+x*(x-3)

determiningTheFunctionDomain
x*(x-3)+7

We multiply parentheses

x^2-3x+7

Back to the equation:

+(x^2-3x+7)



We add all the numbers together, and all the variables

(x^2-3x+7)+8*(x-3))-9*(x=0

We get rid of parentheses

x^2-3x+8*(x-3))-9*(x+7=0

We move all terms containing x to the left, all other terms to the right

x^2-3x+8*(x-3))-9*(x=-7

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