(7/10)(x-4)=42

Solution for (7/10)(x-4)=42 equation:

(7/10)(x-4)=42

We move all terms to the left:

(7/10)(x-4)-(42)=0


Domain of the equation: 10)(x-4)!=0

x∈R


We add all the numbers together, and all the variables

(+7/10)(x-4)-42=0

We multiply parentheses ..

(+7x^2+7/10*-4)-42=0

We multiply all the terms by the denominator


(+7x^2+7-42*10*-4)=0

We get rid of parentheses

7x^2+7-4-42*10*=0

We add all the numbers together, and all the variables

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$