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(7/10)x+1=15
We move all terms to the left:
(7/10)x+1-(15)=0
Domain of the equation: 10)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+7/10)x+1-15=0
We add all the numbers together, and all the variables
(+7/10)x-14=0
We multiply parentheses
7x^2-14=0
a = 7; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·7·(-14)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{2}}{2*7}=\frac{0-14\sqrt{2}}{14} =-\frac{14\sqrt{2}}{14} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{2}}{2*7}=\frac{0+14\sqrt{2}}{14} =\frac{14\sqrt{2}}{14} =\sqrt{2} $
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