(7/10n)+3/5=(2/5n)+2

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Solution for (7/10n)+3/5=(2/5n)+2 equation:



(7/10n)+3/5=(2/5n)+2
We move all terms to the left:
(7/10n)+3/5-((2/5n)+2)=0
Domain of the equation: 10n)!=0
n!=0/1
n!=0
n∈R
Domain of the equation: 5n)+2)!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
(+7/10n)-((+2/5n)+2)+3/5=0
We get rid of parentheses
7/10n-((+2/5n)+2)+3/5=0
We calculate fractions
175n/250n^2+(-((+2*10n)/250n^2+30n/250n^2=0
We can not solve this equation

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