(7/10x+1x)=630

Solution for (7/10x+1x)=630 equation:

(7/10x+1x)=630

We move all terms to the left:

(7/10x+1x)-(630)=0


Domain of the equation: 10x+1x)!=0

x∈R


We add all the numbers together, and all the variables

(+x+7/10x)-630=0

We get rid of parentheses

x+7/10x-630=0

We multiply all the terms by the denominator


x*10x-630*10x+7=0

Wy multiply elements

10x^2-6300x+7=0

a = 10; b = -6300; c = +7;
Δ = b2-4ac
Δ = -63002-4·10·7
Δ = 39689720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39689720}=\sqrt{4*9922430}=\sqrt{4}*\sqrt{9922430}=2\sqrt{9922430}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6300)-2\sqrt{9922430}}{2*10}=\frac{6300-2\sqrt{9922430}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6300)+2\sqrt{9922430}}{2*10}=\frac{6300+2\sqrt{9922430}}{20}
$