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(7/12)a=14

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Solution for (7/12)a=14 equation:



(7/12)a=14
We move all terms to the left:
(7/12)a-(14)=0
Domain of the equation: 12)a!=0
a!=0/1
a!=0
a∈R
We add all the numbers together, and all the variables
(+7/12)a-14=0
We multiply parentheses
7a^2-14=0
a = 7; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·7·(-14)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
a_{1}=\frac{-b-\sqrt{\Delta}}{2a}
a_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:
\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}
a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{2}}{2*7}=\frac{0-14\sqrt{2}}{14} =-\frac{14\sqrt{2}}{14} =-\sqrt{2}
a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{2}}{2*7}=\frac{0+14\sqrt{2}}{14} =\frac{14\sqrt{2}}{14} =\sqrt{2}

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