(7/12)x+(3/4)=2x+(x/4)

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Solution for (7/12)x+(3/4)=2x+(x/4) equation: 



(7/12)x+(3/4)=2x+(x/4)

We move all terms to the left:

(7/12)x+(3/4)-(2x+(x/4))=0



Domain of the equation: 12)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/12)x-(2x+(+x/4))+(+3/4)=0

We multiply parentheses

7x^2-(2x+(+x/4))+(+3/4)=0

We get rid of parentheses

7x^2-(2x+(+x/4))+3/4=0

We calculate fractions


7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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