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(7/12x)-(x)=-5
We move all terms to the left:
(7/12x)-(x)-(-5)=0
Domain of the equation: 12x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+7/12x)-x-(-5)=0
We add all the numbers together, and all the variables
-1x+(+7/12x)+5=0
We get rid of parentheses
-1x+7/12x+5=0
We multiply all the terms by the denominator
-1x*12x+5*12x+7=0
Wy multiply elements
-12x^2+60x+7=0
a = -12; b = 60; c = +7;
Δ = b2-4ac
Δ = 602-4·(-12)·7
Δ = 3936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3936}=\sqrt{16*246}=\sqrt{16}*\sqrt{246}=4\sqrt{246}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{246}}{2*-12}=\frac{-60-4\sqrt{246}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{246}}{2*-12}=\frac{-60+4\sqrt{246}}{-24} $
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