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(7/2)t-2=4+7t
We move all terms to the left:
(7/2)t-2-(4+7t)=0
Domain of the equation: 2)t!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
(+7/2)t-(7t+4)-2=0
We multiply parentheses
7t^2-(7t+4)-2=0
We get rid of parentheses
7t^2-7t-4-2=0
We add all the numbers together, and all the variables
7t^2-7t-6=0
a = 7; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·7·(-6)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:t_{1}=\frac{-b-\sqrt{\Delta}}{2a}t_{2}=\frac{-b+\sqrt{\Delta}}{2a}t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{217}}{2*7}=\frac{7-\sqrt{217}}{14}t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{217}}{2*7}=\frac{7+\sqrt{217}}{14}
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