(7/2)x+20=(4/7)x

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Solution for (7/2)x+20=(4/7)x equation:



(7/2)x+20=(4/7)x
We move all terms to the left:
(7/2)x+20-((4/7)x)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 7)x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+7/2)x-((+4/7)x)+20=0
We multiply parentheses
7x^2-((+4/7)x)+20=0
We multiply all the terms by the denominator
7x^2*7)x)-((+20*7)x)+4=0
We add all the numbers together, and all the variables
7x^2*7)x)-(140x)+4=0
We add all the numbers together, and all the variables
7x^2*7)x)-140x+4=0
Wy multiply elements
49x^3=0
We do not support expression: x^3

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