(7/2)x=x-20+(5/2)x

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Solution for (7/2)x=x-20+(5/2)x equation: 



(7/2)x=x-20+(5/2)x

We move all terms to the left:

(7/2)x-(x-20+(5/2)x)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/2)x-(x-20+(+5/2)x)=0

We multiply parentheses

7x^2-(x-20+(+5/2)x)=0

We multiply all the terms by the denominator


7x^2*2)x)-(x-20+(+5=0

Wy multiply elements

14x^3+5=0

We do not support expression: x^3

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