(7/20)x+(3/28)=(4/35)

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Solution for (7/20)x+(3/28)=(4/35) equation: 



(7/20)x+(3/28)=(4/35)

We move all terms to the left:

(7/20)x+(3/28)-((4/35))=0



Domain of the equation: 20)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/20)x+(+3/28)-((+4/35))=0

We multiply parentheses

7x^2+(+3/28)-((+4/35))=0

We get rid of parentheses

7x^2+3/28-((+4/35))=0

We calculate fractions


7x^2+()/()+()/()=0

We add all the numbers together, and all the variables

7x^2+2=0

a = 7; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·7·2
Δ = -56
Delta is less than zero, so there is no solution for the equation

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