(7/2u+4)+1=(4/u+2)

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Solution for (7/2u+4)+1=(4/u+2) equation: 



(7/2u+4)+1=(4/u+2)

We move all terms to the left:

(7/2u+4)+1-((4/u+2))=0



Domain of the equation: 2u+4)!=0

u∈R





Domain of the equation: u+2))!=0

u∈R



We get rid of parentheses

7/2u-((4/u+2))+4+1=0

We calculate fractions


7u/2u^2+(-((4*2u)/2u^2+4+1=0

We add all the numbers together, and all the variables

7u/2u^2+(-((+4*2u)/2u^2+4+1=0

We calculate fractions

We do not support eupression: u^4

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