(7/2v-10)+1=-(4/v-5)

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Solution for (7/2v-10)+1=-(4/v-5) equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

(7/2)*v-10+1 = -(4/v-5) // + 4/v-5

(7/2)*v+4/v-10-5+1 = 0

7/2*v^1+4*v^-1-14*v^0 = 0

(7/2*v^2-14*v^1+4*v^0)/(v^1) = 0 // * v^2

v^1*(7/2*v^2-14*v^1+4*v^0) = 0

v^1

(7/2)*v^2-14*v+4 = 0

(7/2)*v^2-14*v+4 = 0

DELTA = (-14)^2-(4*4*(7/2))

DELTA = 140

DELTA > 0

v = (140^(1/2)+14)/(2*(7/2)) or v = (14-140^(1/2))/(2*(7/2))

v = (2*35^(1/2)+14)/7 or v = (14-2*35^(1/2))/7

v in { (14-2*35^(1/2))/7, (2*35^(1/2)+14)/7} 

v in { (14-2*35^(1/2))/7, (2*35^(1/2)+14)/7 }

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