(7/2x(x-x))-(8/2x(x+x))=3/2x(2x-1)

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Solution for (7/2x(x-x))-(8/2x(x+x))=3/2x(2x-1) equation: 



(7/2x(x-x))-(8/2x(x+x))=3/2x(2x-1)

We move all terms to the left:

(7/2x(x-x))-(8/2x(x+x))-(3/2x(2x-1))=0



Domain of the equation: 2x(x-x))!=0

x∈R





Domain of the equation: 2x(x+x))!=0

x∈R





Domain of the equation: 2x(2x-1))!=0

x∈R



We add all the numbers together, and all the variables

(7/2x0)-(8/2x(+2x))-(3/2x(2x-1))=0

We get rid of parentheses

7/2x0-(8/2x(+2x))-(3/2x(2x-1))=0

We calculate fractions


(28x^2(+)/(8x^2(+)+(-64x)/(8x^2(+)+(-24x)/(8x^2(+)=0



We calculate terms in parentheses: +(28x^2(+)/(8x^2(+)+(-64x)/(8x^2(+)+(-24x)/(8x^2(+), so:

28x^2(+)/(8x^2(+)+(-64x)/(8x^2(+)+(-24x)/(8x^2(+

We can not solve this equation

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