(7/2x)+(141/2)=(7/x)-10

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Solution for (7/2x)+(141/2)=(7/x)-10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/2)*x+141/2 = 7/x-10 // - 7/x-10

(7/2)*x-(7/x)+141/2+10 = 0

(7/2)*x-7*x^-1+141/2+10 = 0

7/2*x^1-7*x^-1+161/2*x^0 = 0

(7/2*x^2+161/2*x^1-7*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^2+161/2*x^1-7*x^0) = 0

x^1

(7/2)*x^2+(161/2)*x-7 = 0

(7/2)*x^2+(161/2)*x-7 = 0

DELTA = (161/2)^2-(-7*4*(7/2))

DELTA = 26313/4

DELTA > 0

x = ((26313/4)^(1/2)-(161/2))/(2*(7/2)) or x = (-(161/2)-(26313/4)^(1/2))/(2*(7/2))

x = ((26313/4)^(1/2)-161/2)/7 or x = (-((26313/4)^(1/2)+161/2))/7

x in { (-((26313/4)^(1/2)+161/2))/7, ((26313/4)^(1/2)-161/2)/7} 

x in { (-((26313/4)^(1/2)+161/2))/7, ((26313/4)^(1/2)-161/2)/7 }

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