(7/2x+7)(7/3x+7)=0

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Solution for (7/2x+7)(7/3x+7)=0 equation: 


x in (-oo:+oo)

((7/2)*x+7)*((7/3)*x+7) = 0

(7/2*x+7)*(7/3*x+7) = 0

( 7/2*x+7 )

7/2*x+7 = 0 // - 7

7/2*x = -7 // : 7/2

x = -7/7/2

x = -2

( 7/3*x+7 )

7/3*x+7 = 0 // - 7

7/3*x = -7 // : 7/3

x = -7/7/3

x = -3

x in { -2, -3 }

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