(7/2x-8)+1=(-4/x-4)

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Solution for (7/2x-8)+1=(-4/x-4) equation: 



(7/2x-8)+1=(-4/x-4)

We move all terms to the left:

(7/2x-8)+1-((-4/x-4))=0



Domain of the equation: 2x-8)!=0

x∈R





Domain of the equation: x-4))!=0

x∈R



We get rid of parentheses

7/2x-((-4/x-4))-8+1=0

We calculate fractions


7x/2x^2+(-((-4*2x)/2x^2-8+1=0

We calculate fractions

We do not support expression: x^4

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