(7/3)(3x-7)=(2/3)(x-8)

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Solution for (7/3)(3x-7)=(2/3)(x-8) equation: 



(7/3)(3x-7)=(2/3)(x-8)

We move all terms to the left:

(7/3)(3x-7)-((2/3)(x-8))=0



Domain of the equation: 3)(3x-7)!=0

x∈R





Domain of the equation: 3)(x-8))!=0

x∈R



We add all the numbers together, and all the variables

(+7/3)(3x-7)-((+2/3)(x-8))=0

We multiply parentheses ..

(+21x^2+7/3*-7)-((+2/3)(x-8))=0

We calculate fractions


((+21x^2+7*3)(x-8)))/(-7)*3)(x-8))+3*)+()/(-7)*3)(x-8))+3*)=0

We calculate fractions


(((+21x^2+7*3)(x-8)))*(-7)*3)(x-8))+3*))/((*(-7)*3)x)+(-7)*3)(x-8))+3*)+()*()/((*(-7)*3)x)=0

We can not solve this equation

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