(7/3)t=-(6/5)

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Solution for (7/3)t=-(6/5) equation: 



(7/3)t=-(6/5)

We move all terms to the left:

(7/3)t-(-(6/5))=0



Domain of the equation: 3)t!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+7/3)t-(-(+6/5))=0

We multiply parentheses

7t^2-(-(+6/5))=0

We multiply all the terms by the denominator


7t^2*5))-(-(+6=0

Wy multiply elements

35t^3+6=0

We do not support etpression: t^3

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