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(7/3)x+(1/3)x=1+(5/3)x
We move all terms to the left:
(7/3)x+(1/3)x-(1+(5/3)x)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+7/3)x+(+1/3)x-(1+(+5/3)x)=0
We multiply parentheses
7x^2+x^2-(1+(+5/3)x)=0
We multiply all the terms by the denominator
7x^2*3)x)+x^2*3)x)-(1+(+5=0
Wy multiply elements
63x^4=0
We do not support expression: x^4
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