(7/3)x+(2/3)=-18

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Solution for (7/3)x+(2/3)=-18 equation: 



(7/3)x+(2/3)=-18

We move all terms to the left:

(7/3)x+(2/3)-(-18)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/3)x+(+2/3)-(-18)=0

We add all the numbers together, and all the variables

(+7/3)x+18+(+2/3)=0

We multiply parentheses

7x^2+18+(+2/3)=0

We get rid of parentheses

7x^2+18+2/3=0

We multiply all the terms by the denominator


7x^2*3+2+18*3=0

We add all the numbers together, and all the variables

7x^2*3+56=0

Wy multiply elements

21x^2+56=0

a = 21; b = 0; c = +56;
Δ = b2-4ac
Δ = 02-4·21·56
Δ = -4704
Delta is less than zero, so there is no solution for the equation

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