(7/3)y=4

Solution for (7/3)y=4 equation:

(7/3)y=4

We move all terms to the left:

(7/3)y-(4)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+7/3)y-4=0

We multiply parentheses

7y^2-4=0

a = 7; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·7·(-4)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*7}=\frac{0-4\sqrt{7}}{14}
=-\frac{4\sqrt{7}}{14}
=-\frac{2\sqrt{7}}{7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*7}=\frac{0+4\sqrt{7}}{14}
=\frac{4\sqrt{7}}{14}
=\frac{2\sqrt{7}}{7}
$