(7/3)y=42

Solution for (7/3)y=42 equation:

(7/3)y=42

We move all terms to the left:

(7/3)y-(42)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+7/3)y-42=0

We multiply parentheses

7y^2-42=0

a = 7; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·7·(-42)
Δ = 1176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1176}=\sqrt{196*6}=\sqrt{196}*\sqrt{6}=14\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{6}}{2*7}=\frac{0-14\sqrt{6}}{14}
=-\frac{14\sqrt{6}}{14}
=-\sqrt{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{6}}{2*7}=\frac{0+14\sqrt{6}}{14}
=\frac{14\sqrt{6}}{14}
=\sqrt{6}
$