(7/3x)+(10/3x)=16

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Solution for (7/3x)+(10/3x)=16 equation: 



(7/3x)+(10/3x)=16

We move all terms to the left:

(7/3x)+(10/3x)-(16)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/3x)+(+10/3x)-16=0

We get rid of parentheses

7/3x+10/3x-16=0

We multiply all the terms by the denominator


-16*3x+7+10=0

We add all the numbers together, and all the variables

-16*3x+17=0

Wy multiply elements

-48x+17=0

We move all terms containing x to the left, all other terms to the right

-48x=-17

x=-17/-48

x=17/48

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