(7/3x+1)-(18x/3x-1)=-6

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Solution for (7/3x+1)-(18x/3x-1)=-6 equation: 



(7/3x+1)-(18x/3x-1)=-6

We move all terms to the left:

(7/3x+1)-(18x/3x-1)-(-6)=0



Domain of the equation: 3x+1)!=0

x∈R





Domain of the equation: 3x-1)!=0

x∈R



We add all the numbers together, and all the variables

(7/3x+1)-(18x/3x-1)+6=0

We get rid of parentheses

7/3x-18x/3x+1+1+6=0

We multiply all the terms by the denominator


-18x+1*3x+1*3x+6*3x+7=0

Wy multiply elements

-18x+3x+3x+18x+7=0

We add all the numbers together, and all the variables

6x+7=0

We move all terms containing x to the left, all other terms to the right

6x=-7

x=-7/6

x=-1+1/6

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